{"id":14350,"date":"2012-04-13T09:35:31","date_gmt":"2012-04-13T08:35:31","guid":{"rendered":"http:\/\/agert.homelinux.org\/WorldPress\/?page_id=14350"},"modified":"2014-12-22T18:50:10","modified_gmt":"2014-12-22T17:50:10","slug":"svar-dackproblemet","status":"publish","type":"page","link":"https:\/\/fatherben.se\/wordpress\/father-ben\/om\/21501\/d\/profile-father-ben-site\/svar-dackproblemet\/","title":{"rendered":"Svar D\u00e4ckproblemet"},"content":{"rendered":"<p><strong>En ungef\u00e4rlig bed\u00f6mning \u00a0<\/strong><\/p>\n<p>D\u00e4cken h\u00e5ller fram 3500 mil och d\u00e4cken bak 4300 mil \u00e4r vanlig f\u00f6rdelning p\u00e5 en framhjulsdriven st\u00f6rre bil med 150-200 hk<\/p>\n<p>En bra uppskattning s\u00e4ger att bilen kan k\u00f6ras \u00a0ca (3500+4300) \/2=<em><strong>3900 mil<\/strong><\/em> \u00a0och man b\u00f6r byta ungef\u00e4r efter\u00a0ca\u00a0<strong>1950 mil.\u00a0<\/strong><\/p>\n<p><em>\u00a0<\/em><strong>DET \u00c4R ETT GODK\u00c4NT SVAR\u00a0<\/strong><\/p>\n<p><strong>En exakt ber\u00e4kning med en ekvation<\/strong><\/p>\n<p><em>ger byte efter 1930 mil och alla fyra d\u00e4cken \u00e4r utslitna efter \u00a0 3860 mil \u00a0<\/em><\/p>\n<p><strong>Matematiskt utr\u00e4knat<\/strong><\/p>\n<p>D\u00e4cken varar \u00a0a mil fram och b mil bak som \u00e4r k\u00e4nda\u00a0uppgifter<\/p>\n<p>D\u00e4cken m\u00e5ste skiftas efter x mil<\/p>\n<p><strong>D\u00e4ck \u00a0fram<\/strong>\u00a0 (a) g\u00e5r x mil fram och b\/a*(a-x) mil \u00a0bak &#8211; (a-x \u00a0 \u00e4r str\u00e4ckan som d\u00e4cket\u00a0\u00a0rullar bak om det varit\u00a0samma f\u00f6rslitning som fram som m\u00e5ste\u00a0korrigeras med\u00a0b\/a\u00a0\u00a0slitageskillnaden fram och\u00a0bak) \u00a0eller sammanlagt \u00a0S= <span style=\"color: #339966;\">\u00a0x+b(a-x)\/a<\/span> mil<\/p>\n<p>K\u00f6rstr\u00e4ckan \u00a0 S\u00a0= <span style=\"color: #ff0000;\">2x<\/span>\u00a0 \u00a0N\u00e4r man byter efter x mil s\u00e5 m\u00e5ste det vara x mil kvar f\u00f6r b\u00e5da d\u00e4cken i bytt position d\u00e5 d\u00e4cken ju slits i viss proportion i f\u00f6rh\u00e5llande till varandra n\u00e4r de sitter fram och bak<\/p>\n<p>Anv\u00e4nder man sig av den senare insikten har\u00a0den sammanlagda k\u00f6rstr\u00e4ckan\u00a0formulerats p\u00e5 tv\u00e5\u00a0s\u00e4tt<\/p>\n<p>S=<span style=\"color: #ff0000;\">2x<\/span><\/p>\n<p>S= <span style=\"color: #339966;\">\u00a0x+b(a-x)\/a<\/span><\/p>\n<p>&nbsp;<\/p>\n<p>dvs 2x=x+b(a-x)\/a<\/p>\n<p>Det ger vid l\u00f6sning av ekvationen med algebran \u00a0<strong>x=ab\/(b+a)<\/strong>\u00a0och \u00a0<strong>s=2x \u00a0vet vi redan\u00a0<\/strong>d\u00e4r x \u00e4r miltal vid d\u00e4cksbyte och s \u00e4r miltalet n\u00e4r d\u00e4cken \u00e4r \u00a0utslitna, a \u00e4r milstr\u00e4cka fram och b\u00e4r \u00a0milstr\u00e4cka bak om man inte byter d\u00e4ck<\/p>\n<p><strong>OPTIMALT BYTE<\/strong><\/p>\n<p><strong>x=ab\/(b+a)<\/strong> \u00a0dvs x= 3500*4300\/7800 = <strong>1930 \u00a0mil d\u00e5 \u00e4r det dax f\u00f6r d\u00e4cksbyte\u00a0<\/strong><\/p>\n<p><strong>D\u00e4cken kan rulla\u00a0s= 2x<\/strong> \u00a0dvs 2 * 1930 =\u00a0<strong>3860<\/strong>\u00a0<strong>\u00a0mil d\u00e5 \u00e4r alla 4 d\u00e4cken utslitna<\/strong><\/p>\n<p><strong><br \/>\n<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>En ungef\u00e4rlig bed\u00f6mning \u00a0 D\u00e4cken h\u00e5ller fram 3500 mil och d\u00e4cken bak 4300 mil \u00e4r vanlig f\u00f6rdelning p\u00e5 en framhjulsdriven st\u00f6rre bil med 150-200 hk En bra uppskattning s\u00e4ger att bilen kan k\u00f6ras \u00a0ca (3500+4300) \/2=3900 mil \u00a0och man b\u00f6r byta ungef\u00e4r efter\u00a0ca\u00a01950 mil.\u00a0 \u00a0DET \u00c4R ETT GODK\u00c4NT SVAR\u00a0 En exakt ber\u00e4kning med en ekvation [&hellip;]<\/p>\n","protected":false},"author":5,"featured_media":0,"parent":3113,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":["post-14350","page","type-page","status-publish","hentry"],"jetpack_shortlink":"https:\/\/wp.me\/P1IAXy-3Js","jetpack_sharing_enabled":true,"jetpack-related-posts":[{"id":36176,"url":"https:\/\/fatherben.se\/wordpress\/ladderfarenheter-niro-ev\/","url_meta":{"origin":14350,"position":0},"title":"LADDERFARENHETER NIRO EV","author":"admin","date":"2024-06-03","format":false,"excerpt":"uppdaterad 240718 LADDSTRATEGI f\u00f6r min elbil juni 2024 LADDKURVAN F\u00f6rsta laddningen p\u00e5 Eviny\u00a0 (app BILKRAFT)\u00a0 Ronneby ICA maxi 2 juni 52%-75%\u00a0 15 kwh 25 minute 33 KW i snitt borde ha varit\u00a0 55Kw Lite strul med KIA kort och app hade tv\u00e5 sessioner ig\u00e5ng men laddade bara p\u00e5 en. 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